Soi c\u1ea7u pascal mb theo gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0 gi\u1ea3i nh\u1ea5t<\/strong><\/h3>\n\u0110\u1ed1i v\u1edbi ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u pascal n\u00e0y. Th\u00ec anh em ng\u01b0\u1eddi ch\u01a1i s\u1ebd ti\u1ebfn h\u00e0nh d\u1ef1a tr\u00ean d\u00e3y s\u1ed1 v\u1ec1 gi\u1ea3i nh\u1ea5t v\u00e0 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a k\u1ef3 quay th\u01b0\u1edfng tr\u01b0\u1edbc \u0111\u00f3.<\/p>\n
Sau \u0111\u00f3 th\u00ec ch\u00fang ta s\u1ebd th\u1ef1c hi\u1ec7n c\u00e1ch soi c\u1ea7u pascal anh em ch\u00fang ta l\u1ea5y 2 s\u1ed1 c\u1ea1nh nhau. Sau \u0111\u00f3 c\u1ed9ng l\u1ea1i v\u00e0 ch\u00fang ta s\u1ebd l\u00e0m li\u00ean t\u1ee5c nh\u01b0 v\u1eady cho \u0111\u1ebfn khi m\u00e0 c\u00e1c d\u00e3y s\u1ed1 v\u1ec1 l\u00e0 m\u1ed9t s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 th\u00ec d\u1eebng.<\/p>\n
V\u1edbi ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u00fang ta c\u00f3 th\u1ec3 soi c\u1ea7u c\u1ee5 th\u1ec3 b\u1eb1ng c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 theo c\u1ea7u pascal. Khi n\u00e0y ch\u00fang ta th\u1ef1c hi\u1ec7n nh\u01b0 sau:<\/p>\n
V\u00ed d\u1ee5 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 12345 v\u00e0 gi\u1ea3i nh\u1ea5t l\u00e0 67890, gh\u00e9p l\u1ea1i ta \u0111\u01b0\u1ee3c 1234567890<\/p>\n
l\u1ea5y 1 + 2, 2+ 3, 3 + 4\u2026.<\/p>\n
L\u00e0m t\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady v\u1edbi k\u1ebft qu\u1ea3 nh\u1eadn \u0111\u01b0\u1ee3c<\/p>\n
L\u01b0u \u00fd:<\/p>\n
\u2013 N\u1ebfu nh\u01b0 m\u00e0 2 s\u1ed1 c\u1ed9ng l\u1ea1i > 10 th\u00ec ch\u1ec9 l\u1ea5y s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb<\/p>\n
\u2013 C\u00f2n n\u1ebfu 2 s\u1ed1 c\u1ed9ng l\u1ea1i < 10 th\u00ec l\u1ea5y ch\u00ednh s\u1ed1 \u0111\u00f3 \u0111\u1ec3 th\u1ef1c hi\u1ec7n ti\u1ebfp.<\/p>\n
K\u1ebft qu\u1ea3 nh\u1eadn \u0111\u01b0\u1ee3c s\u1ebd l\u00e0 1 s\u1ed1 XY khi n\u00e0y anh em s\u1ebd l\u1ea5y XY \u2013 YX l\u00e0m c\u1ea7u nu\u00f4i ng\u00e0y h\u00f4m sau. T\u1ef7 l\u1ec7 c\u1ea7u v\u1ec1 theo c\u00e1ch n\u00e0y l\u00e0 kh\u00e1 cao. C\u1ea7u n\u00e0y th\u01b0\u1eddng v\u1ec1 v\u00e0o ng\u00e0y h\u00f4m sau th\u1ebf nh\u01b0ng c\u0169ng c\u00f3 nh\u1eefng c\u1ea7u v\u1ec1 v\u00e0o ng\u00e0y th\u1ee9 2 ch\u00ednh v\u00ec v\u1eady cho n\u00ean ng\u01b0\u1eddi ch\u01a1i l\u00ean nu\u00f4i khung 2 ng\u00e0y<\/strong>, 3 ng\u00e0y l\u00e0 chu\u1ea9n nh\u1ea5t.<\/p>\nVd c\u1ee5 th\u1ec3:<\/p>\n